log[4](2x+14)-log[4](2x-1)=2

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Solution for log[4](2x+14)-log[4](2x-1)=2 equation: 


Simplifying
log[4](2x + 14) + -1log[4](2x + -1) = 2

Reorder the terms:
glo * 4(14 + 2x) + -1log[4](2x + -1) = 2

Reorder the terms for easier multiplication:
4glo(14 + 2x) + -1log[4](2x + -1) = 2
(14 * 4glo + 2x * 4glo) + -1log[4](2x + -1) = 2
(56glo + 8glox) + -1log[4](2x + -1) = 2

Reorder the terms:
56glo + 8glox + -1glo * 4(-1 + 2x) = 2

Reorder the terms for easier multiplication:
56glo + 8glox + -1 * 4glo(-1 + 2x) = 2

Multiply -1 * 4
56glo + 8glox + -4glo(-1 + 2x) = 2
56glo + 8glox + (-1 * -4glo + 2x * -4glo) = 2
56glo + 8glox + (4glo + -8glox) = 2

Reorder the terms:
56glo + 4glo + 8glox + -8glox = 2

Combine like terms: 56glo + 4glo = 60glo
60glo + 8glox + -8glox = 2

Combine like terms: 8glox + -8glox = 0
60glo + 0 = 2
60glo = 2

Solving
60glo = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '60lo'.
g = 0.03333333333l-1o-1

Simplifying
g = 0.03333333333l-1o-1

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